Base | Representation |
---|---|
bin | 100101101000010110011111… |
… | …1100000001110011001001111 |
3 | 1121101222102020102002022211112 |
4 | 1023100230333200032121033 |
5 | 321341111140330404012 |
6 | 3131551522544042235 |
7 | 126502025012641244 |
oct | 11320547740163117 |
9 | 1541872212068745 |
10 | 331001310013007 |
11 | 9651595a352647 |
12 | 3115a33100337b |
13 | 1129039c34230a |
14 | 5ba47981d55cb |
15 | 2840184dbb122 |
hex | 12d0b3f80e64f |
331001310013007 has 2 divisors, whose sum is σ = 331001310013008. Its totient is φ = 331001310013006.
The previous prime is 331001310012797. The next prime is 331001310013009. The reversal of 331001310013007 is 700310013100133.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 331001310013007 - 228 = 331001041577551 is a prime.
Together with 331001310013009, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (331001310013009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165500655006503 + 165500655006504.
It is an arithmetic number, because the mean of its divisors is an integer number (165500655006504).
Almost surely, 2331001310013007 is an apocalyptic number.
331001310013007 is a deficient number, since it is larger than the sum of its proper divisors (1).
331001310013007 is an equidigital number, since it uses as much as digits as its factorization.
331001310013007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 567, while the sum is 23.
The spelling of 331001310013007 in words is "three hundred thirty-one trillion, one billion, three hundred ten million, thirteen thousand, seven".
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