Base | Representation |
---|---|
bin | 1001101000100010100… |
… | …10000001101101000000 |
3 | 1011122101010110010220002 |
4 | 10310101102001231000 |
5 | 20410343104420112 |
6 | 412021014335132 |
7 | 32625356101514 |
oct | 4642122015500 |
9 | 1148333403802 |
10 | 331002420032 |
11 | 118417267339 |
12 | 5419805a4a8 |
13 | 252a0a9a54b |
14 | 12040768144 |
15 | 89242e61c2 |
hex | 4d11481b40 |
331002420032 has 14 divisors (see below), whose sum is σ = 656832927378. Its totient is φ = 165501209984.
The previous prime is 331002419947. The next prime is 331002420053. The reversal of 331002420032 is 230024200133.
It can be written as a sum of positive squares in only one way, i.e., 265084938496 + 65917481536 = 514864^2 + 256744^2 .
It is a junction number, because it is equal to n+sod(n) for n = 331002419986 and 331002420013.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2585956343 + ... + 2585956470.
Almost surely, 2331002420032 is an apocalyptic number.
331002420032 is a gapful number since it is divisible by the number (32) formed by its first and last digit.
It is an amenable number.
331002420032 is a deficient number, since it is larger than the sum of its proper divisors (325830507346).
331002420032 is an equidigital number, since it uses as much as digits as its factorization.
331002420032 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5171912825 (or 5171912815 counting only the distinct ones).
The product of its (nonzero) digits is 864, while the sum is 20.
Adding to 331002420032 its reverse (230024200133), we get a palindrome (561026620165).
The spelling of 331002420032 in words is "three hundred thirty-one billion, two million, four hundred twenty thousand, thirty-two".
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