Base | Representation |
---|---|
bin | 1111000011010111101010… |
… | …01110001110011011010111 |
3 | 11100012102210210220112120221 |
4 | 13201223311032032123113 |
5 | 13314312104311130012 |
6 | 154222241123135211 |
7 | 6654322624514344 |
oct | 741536516163327 |
9 | 140172723815527 |
10 | 33101132130007 |
11 | a602125162967 |
12 | 386727a214507 |
13 | 156156719bba6 |
14 | 8261638077cb |
15 | 3c6082d38507 |
hex | 1e1af538e6d7 |
33101132130007 has 2 divisors, whose sum is σ = 33101132130008. Its totient is φ = 33101132130006.
The previous prime is 33101132129999. The next prime is 33101132130049. The reversal of 33101132130007 is 70003123110133.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 33101132130007 - 23 = 33101132129999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (33101132130707) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16550566065003 + 16550566065004.
It is an arithmetic number, because the mean of its divisors is an integer number (16550566065004).
Almost surely, 233101132130007 is an apocalyptic number.
33101132130007 is a deficient number, since it is larger than the sum of its proper divisors (1).
33101132130007 is an equidigital number, since it uses as much as digits as its factorization.
33101132130007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1134, while the sum is 25.
The spelling of 33101132130007 in words is "thirty-three trillion, one hundred one billion, one hundred thirty-two million, one hundred thirty thousand, seven".
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