331013201100341 has 2 divisors, whose sum is σ = 331013201100342. Its totient is φ = 331013201100340.

The previous prime is 331013201100293. The next prime is 331013201100343. The reversal of 331013201100341 is 143001102310133.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 329337962724241 + 1675238376100 = 18147671^2 + 1294310^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-331013201100341 is a prime.

Together with 331013201100343, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (331013201100343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165506600550170 + 165506600550171.

It is an arithmetic number, because the mean of its divisors is an integer number (165506600550171).

Almost surely, 2^{331013201100341} is an apocalyptic number.

It is an amenable number.

331013201100341 is a deficient number, since it is larger than the sum of its proper divisors (1).

331013201100341 is an equidigital number, since it uses as much as digits as its factorization.

331013201100341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 331013201100341 its reverse (143001102310133), we get a palindrome (474014303410474).

The spelling of 331013201100341 in words is "three hundred thirty-one trillion, thirteen billion, two hundred one million, one hundred thousand, three hundred forty-one".