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331102113120 = 253253710875717
BaseRepresentation
bin1001101000101110011…
…10010100110101100000
31011122122002001002002200
410310113032110311200
520411044120104440
6412034535213200
732631006345102
oct4642716246540
91148562032080
10331102113120
11118468569219
1254205517200
13252b863443c
141204dab9572
15892ce39c30
hex4d17394d60

331102113120 has 288 divisors, whose sum is σ = 1161694130688. Its totient is φ = 85813530624.

The previous prime is 331102113119. The next prime is 331102113161. The reversal of 331102113120 is 21311201133.

331102113120 is a `hidden beast` number, since 33 + 110 + 211 + 312 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (288).

It is a super-2 number, since 2×3311021131202 (a number of 24 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 331102113093 and 331102113102.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 57912502 + ... + 57918218.

It is an arithmetic number, because the mean of its divisors is an integer number (4033660176).

Almost surely, 2331102113120 is an apocalyptic number.

331102113120 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 331102113120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (580847065344).

331102113120 is an abundant number, since it is smaller than the sum of its proper divisors (830592017568).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

331102113120 is a wasteful number, since it uses less digits than its factorization.

331102113120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6862 (or 6851 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 331102113120 its reverse (21311201133), we get a palindrome (352413314253).

The spelling of 331102113120 in words is "three hundred thirty-one billion, one hundred two million, one hundred thirteen thousand, one hundred twenty".