Base | Representation |
---|---|
bin | 100101101001001010111111… |
… | …0001001100111100111010101 |
3 | 1121102101012012002000012001012 |
4 | 1023102111332021213213111 |
5 | 321344433013212420201 |
6 | 3132115404024542005 |
7 | 126513125224506644 |
oct | 11322257611474725 |
9 | 1542335162005035 |
10 | 331114030201301 |
11 | 96559742a18456 |
12 | 3117814a921905 |
13 | 1129abc4273999 |
14 | 5baa00c78535b |
15 | 2843080bd55bb |
hex | 12d257e2679d5 |
331114030201301 has 2 divisors, whose sum is σ = 331114030201302. Its totient is φ = 331114030201300.
The previous prime is 331114030201267. The next prime is 331114030201303. The reversal of 331114030201301 is 103102030411133.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 258407200352401 + 72706829848900 = 16075049^2 + 8526830^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-331114030201301 is a prime.
It is a super-2 number, since 2×3311140302013012 (a number of 30 digits) contains 22 as substring.
It is a Sophie Germain prime.
Together with 331114030201303, it forms a pair of twin primes.
It is a Chen prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (331114030201303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165557015100650 + 165557015100651.
It is an arithmetic number, because the mean of its divisors is an integer number (165557015100651).
Almost surely, 2331114030201301 is an apocalyptic number.
It is an amenable number.
331114030201301 is a deficient number, since it is larger than the sum of its proper divisors (1).
331114030201301 is an equidigital number, since it uses as much as digits as its factorization.
331114030201301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 331114030201301 its reverse (103102030411133), we get a palindrome (434216060612434).
The spelling of 331114030201301 in words is "three hundred thirty-one trillion, one hundred fourteen billion, thirty million, two hundred one thousand, three hundred one".
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