Base | Representation |
---|---|
bin | 11110110101101000… |
… | …010000101001011010 |
3 | 10011110122001221100122 |
4 | 132311220100221122 |
5 | 1020303133013424 |
6 | 23113401033242 |
7 | 2251355236253 |
oct | 366550205132 |
9 | 104418057318 |
10 | 33112001114 |
11 | 13051952585 |
12 | 6501185822 |
13 | 317903278a |
14 | 1861887b2a |
15 | cdbe4345e |
hex | 7b5a10a5a |
33112001114 has 32 divisors (see below), whose sum is σ = 51807879936. Its totient is φ = 15859247040.
The previous prime is 33112001071. The next prime is 33112001137. The reversal of 33112001114 is 41110021133.
It is a junction number, because it is equal to n+sod(n) for n = 33112001092 and 33112001101.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2089529 + ... + 2105315.
It is an arithmetic number, because the mean of its divisors is an integer number (1618996248).
Almost surely, 233112001114 is an apocalyptic number.
33112001114 is a deficient number, since it is larger than the sum of its proper divisors (18695878822).
33112001114 is a wasteful number, since it uses less digits than its factorization.
33112001114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16310.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 33112001114 its reverse (41110021133), we get a palindrome (74222022247).
The spelling of 33112001114 in words is "thirty-three billion, one hundred twelve million, one thousand, one hundred fourteen".
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