Base | Representation |
---|---|
bin | 110000001011111000111… |
… | …111001100000110011011 |
3 | 102201120001100011002210021 |
4 | 300023320333030012123 |
5 | 413223021321211443 |
6 | 11013105144331311 |
7 | 461143103502106 |
oct | 60137077140633 |
9 | 12646040132707 |
10 | 3311302132123 |
11 | 1067351801137 |
12 | 455904473b37 |
13 | 1b034004c54b |
14 | b63a70b573d |
15 | 5b2042729ed |
hex | 302f8fcc19b |
3311302132123 has 2 divisors, whose sum is σ = 3311302132124. Its totient is φ = 3311302132122.
The previous prime is 3311302132121. The next prime is 3311302132231. The reversal of 3311302132123 is 3212312031133.
Together with next prime (3311302132231) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is an emirp because it is prime and its reverse (3212312031133) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3311302132123 - 21 = 3311302132121 is a prime.
Together with 3311302132121, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (3311302132121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1655651066061 + 1655651066062.
It is an arithmetic number, because the mean of its divisors is an integer number (1655651066062).
Almost surely, 23311302132123 is an apocalyptic number.
3311302132123 is a deficient number, since it is larger than the sum of its proper divisors (1).
3311302132123 is an equidigital number, since it uses as much as digits as its factorization.
3311302132123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 3311302132123 its reverse (3212312031133), we get a palindrome (6523614163256).
The spelling of 3311302132123 in words is "three trillion, three hundred eleven billion, three hundred two million, one hundred thirty-two thousand, one hundred twenty-three".
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