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331131131202253 is a prime number
BaseRepresentation
bin100101101001010010111100…
…1011100110000101011001101
31121102102211022212120001012211
41023102211321130300223031
5321400223024041433003
63132131312554430421
7126514302055562404
oct11322457134605315
91542384285501184
10331131131202253
1196565a18aa1598
123117b521a32411
131129c6bb16b365
145baab91a3663b
1528437321ad96d
hex12d2979730acd

331131131202253 has 2 divisors, whose sum is σ = 331131131202254. Its totient is φ = 331131131202252.

The previous prime is 331131131202103. The next prime is 331131131202269. The reversal of 331131131202253 is 352202131131133.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 221071162245444 + 110059968956809 = 14868462^2 + 10490947^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-331131131202253 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (331131131202953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165565565601126 + 165565565601127.

It is an arithmetic number, because the mean of its divisors is an integer number (165565565601127).

Almost surely, 2331131131202253 is an apocalyptic number.

It is an amenable number.

331131131202253 is a deficient number, since it is larger than the sum of its proper divisors (1).

331131131202253 is an equidigital number, since it uses as much as digits as its factorization.

331131131202253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9720, while the sum is 31.

Adding to 331131131202253 its reverse (352202131131133), we get a palindrome (683333262333386).

The spelling of 331131131202253 in words is "three hundred thirty-one trillion, one hundred thirty-one billion, one hundred thirty-one million, two hundred two thousand, two hundred fifty-three".