Base | Representation |
---|---|
bin | 100101101001010010111100… |
… | …1011100110000101000110111 |
3 | 1121102102211022212120001000021 |
4 | 1023102211321130300220313 |
5 | 321400223024041431403 |
6 | 3132131312554430011 |
7 | 126514302055562101 |
oct | 11322457134605067 |
9 | 1542384285501007 |
10 | 331131131202103 |
11 | 96565a18aa1471 |
12 | 3117b521a32307 |
13 | 1129c6bb16b27b |
14 | 5baab91a36571 |
15 | 28437321ad8bd |
hex | 12d2979730a37 |
331131131202103 has 2 divisors, whose sum is σ = 331131131202104. Its totient is φ = 331131131202102.
The previous prime is 331131131202043. The next prime is 331131131202253. The reversal of 331131131202103 is 301202131131133.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 331131131202103 - 237 = 330993692248631 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (331131131206103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165565565601051 + 165565565601052.
It is an arithmetic number, because the mean of its divisors is an integer number (165565565601052).
Almost surely, 2331131131202103 is an apocalyptic number.
331131131202103 is a deficient number, since it is larger than the sum of its proper divisors (1).
331131131202103 is an equidigital number, since it uses as much as digits as its factorization.
331131131202103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 331131131202103 its reverse (301202131131133), we get a palindrome (632333262333236).
The spelling of 331131131202103 in words is "three hundred thirty-one trillion, one hundred thirty-one billion, one hundred thirty-one million, two hundred two thousand, one hundred three".
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