Base | Representation |
---|---|
bin | 100101101001010011000001… |
… | …1100001100011111110001101 |
3 | 1121102102211202122121200221121 |
4 | 1023102212003201203332031 |
5 | 321400223400324424401 |
6 | 3132131341433400541 |
7 | 126514306210403614 |
oct | 11322460341437615 |
9 | 1542384678550847 |
10 | 331131300233101 |
11 | 96565aa5451a05 |
12 | 3117b56a569151 |
13 | 1129c7171a1504 |
14 | 5baabaa27687b |
15 | 2843741e4bca1 |
hex | 12d2983863f8d |
331131300233101 has 2 divisors, whose sum is σ = 331131300233102. Its totient is φ = 331131300233100.
The previous prime is 331131300233093. The next prime is 331131300233147. The reversal of 331131300233101 is 101332003131133.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 326335156433001 + 4796143800100 = 18064749^2 + 2190010^2 .
It is a cyclic number.
It is not a de Polignac number, because 331131300233101 - 23 = 331131300233093 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (331131300236101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165565650116550 + 165565650116551.
It is an arithmetic number, because the mean of its divisors is an integer number (165565650116551).
Almost surely, 2331131300233101 is an apocalyptic number.
It is an amenable number.
331131300233101 is a deficient number, since it is larger than the sum of its proper divisors (1).
331131300233101 is an equidigital number, since it uses as much as digits as its factorization.
331131300233101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 331131300233101 its reverse (101332003131133), we get a palindrome (432463303364234).
The spelling of 331131300233101 in words is "three hundred thirty-one trillion, one hundred thirty-one billion, three hundred million, two hundred thirty-three thousand, one hundred one".
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