Base | Representation |
---|---|
bin | 1001101000110010000… |
… | …00011000101000111101 |
3 | 1011122201011022011011222 |
4 | 10310121000120220331 |
5 | 20411124243404432 |
6 | 412041524123125 |
7 | 32631521446103 |
oct | 4643100305075 |
9 | 1148634264158 |
10 | 331132013117 |
11 | 118483430564 |
12 | 542135364a5 |
13 | 252c18a2a49 |
14 | 12053a5dc73 |
15 | 8930894112 |
hex | 4d19018a3d |
331132013117 has 2 divisors, whose sum is σ = 331132013118. Its totient is φ = 331132013116.
The previous prime is 331132013011. The next prime is 331132013159. The reversal of 331132013117 is 711310231133.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 271637973721 + 59494039396 = 521189^2 + 243914^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-331132013117 is a prime.
It is a super-2 number, since 2×3311320131172 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (331132013417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165566006558 + 165566006559.
It is an arithmetic number, because the mean of its divisors is an integer number (165566006559).
Almost surely, 2331132013117 is an apocalyptic number.
It is an amenable number.
331132013117 is a deficient number, since it is larger than the sum of its proper divisors (1).
331132013117 is an equidigital number, since it uses as much as digits as its factorization.
331132013117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1134, while the sum is 26.
The spelling of 331132013117 in words is "three hundred thirty-one billion, one hundred thirty-two million, thirteen thousand, one hundred seventeen".
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