Base | Representation |
---|---|
bin | 1100010101101011… |
… | …0100100000111101 |
3 | 22112211101021012122 |
4 | 3011122310200331 |
5 | 23240402024042 |
6 | 1304354412325 |
7 | 145035513554 |
oct | 30532644075 |
9 | 8484337178 |
10 | 3312142397 |
11 | 144a688673 |
12 | 7852910a5 |
13 | 40a274095 |
14 | 235c5ad9b |
15 | 145ba07d2 |
hex | c56b483d |
3312142397 has 2 divisors, whose sum is σ = 3312142398. Its totient is φ = 3312142396.
The previous prime is 3312142367. The next prime is 3312142399. The reversal of 3312142397 is 7932412133.
3312142397 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2590199236 + 721943161 = 50894^2 + 26869^2 .
It is a cyclic number.
It is not a de Polignac number, because 3312142397 - 210 = 3312141373 is a prime.
Together with 3312142399, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3312142399) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1656071198 + 1656071199.
It is an arithmetic number, because the mean of its divisors is an integer number (1656071199).
Almost surely, 23312142397 is an apocalyptic number.
It is an amenable number.
3312142397 is a deficient number, since it is larger than the sum of its proper divisors (1).
3312142397 is an equidigital number, since it uses as much as digits as its factorization.
3312142397 is an evil number, because the sum of its binary digits is even.
The product of its digits is 27216, while the sum is 35.
The square root of 3312142397 is about 57551.2154259143. The cubic root of 3312142397 is about 1490.6293449687.
The spelling of 3312142397 in words is "three billion, three hundred twelve million, one hundred forty-two thousand, three hundred ninety-seven".
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