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331322013131 is a prime number
BaseRepresentation
bin1001101001001000101…
…01001011010111001011
31011200012101211011012112
410310210111023113023
520412021413410011
6412112432332535
732636316434024
oct4644425132713
91150171734175
10331322013131
1111857070336a
12542670a414b
13253220684a5
1412070d9bc4b
1589423c558b
hex4d2454b5cb

331322013131 has 2 divisors, whose sum is σ = 331322013132. Its totient is φ = 331322013130.

The previous prime is 331322013103. The next prime is 331322013133. The reversal of 331322013131 is 131310223133.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-331322013131 is a prime.

It is a super-2 number, since 2×3313220131312 (a number of 24 digits) contains 22 as substring.

Together with 331322013133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 331322013097 and 331322013106.

It is not a weakly prime, because it can be changed into another prime (331322013133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165661006565 + 165661006566.

It is an arithmetic number, because the mean of its divisors is an integer number (165661006566).

Almost surely, 2331322013131 is an apocalyptic number.

331322013131 is a deficient number, since it is larger than the sum of its proper divisors (1).

331322013131 is an equidigital number, since it uses as much as digits as its factorization.

331322013131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 331322013131 its reverse (131310223133), we get a palindrome (462632236264).

The spelling of 331322013131 in words is "three hundred thirty-one billion, three hundred twenty-two million, thirteen thousand, one hundred thirty-one".