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331333313030149 is a prime number
BaseRepresentation
bin100101101010110001000110…
…0011011001110100000000101
31121110011011012021100001220211
41023111202030123032200011
5321412031111113431044
63132404231144555421
7126535020242011603
oct11325421433164005
91543134167301824
10331333313030149
119663373a400341
12311b2748182b71
13112b579c4c8751
145bb68917c4873
152848b16e60634
hex12d588c6ce805

331333313030149 has 2 divisors, whose sum is σ = 331333313030150. Its totient is φ = 331333313030148.

The previous prime is 331333313030147. The next prime is 331333313030243. The reversal of 331333313030149 is 941030313333133.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 231249655541025 + 100083657489124 = 15206895^2 + 10004182^2 .

It is an emirp because it is prime and its reverse (941030313333133) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 331333313030149 - 21 = 331333313030147 is a prime.

Together with 331333313030147, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (331333313030147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165666656515074 + 165666656515075.

It is an arithmetic number, because the mean of its divisors is an integer number (165666656515075).

Almost surely, 2331333313030149 is an apocalyptic number.

It is an amenable number.

331333313030149 is a deficient number, since it is larger than the sum of its proper divisors (1).

331333313030149 is an equidigital number, since it uses as much as digits as its factorization.

331333313030149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 236196, while the sum is 40.

The spelling of 331333313030149 in words is "three hundred thirty-one trillion, three hundred thirty-three billion, three hundred thirteen million, thirty thousand, one hundred forty-nine".