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3313450412381 is a prime number
BaseRepresentation
bin110000001101111001000…
…010001110100101011101
3102201202121001112001021202
4300031321002032211131
5413241421301144011
611014102245405245
7461250250541624
oct60157102164535
912652531461252
103313450412381
11106825441596a
12456203a09825
131b05c3142ab5
14b652c52c6bb
155b2ccb7523b
hex3037908e95d

3313450412381 has 2 divisors, whose sum is σ = 3313450412382. Its totient is φ = 3313450412380.

The previous prime is 3313450412351. The next prime is 3313450412521. The reversal of 3313450412381 is 1832140543133.

3313450412381 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1695440972281 + 1618009440100 = 1302091^2 + 1272010^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3313450412381 is a prime.

It is a super-2 number, since 2×33134504123812 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3313450412351) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1656725206190 + 1656725206191.

It is an arithmetic number, because the mean of its divisors is an integer number (1656725206191).

Almost surely, 23313450412381 is an apocalyptic number.

It is an amenable number.

3313450412381 is a deficient number, since it is larger than the sum of its proper divisors (1).

3313450412381 is an equidigital number, since it uses as much as digits as its factorization.

3313450412381 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 103680, while the sum is 38.

The spelling of 3313450412381 in words is "three trillion, three hundred thirteen billion, four hundred fifty million, four hundred twelve thousand, three hundred eighty-one".