33140111 has 2 divisors, whose sum is σ = 33140112. Its totient is φ = 33140110.

The previous prime is 33140099. The next prime is 33140113. The reversal of 33140111 is 11104133.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-33140111 is a prime.

Together with 33140113, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (33140113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16570055 + 16570056.

It is an arithmetic number, because the mean of its divisors is an integer number (16570056).

Almost surely, 2^33140111 is an apocalyptic number.

33140111 is a deficient number, since it is larger than the sum of its proper divisors (1).

33140111 is an equidigital number, since it uses as much as digits as its factorization.

33140111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 14.

The square root of 33140111 is about 5756.7448267228. The cubic root of 33140111 is about 321.2067423977.

Adding to 33140111 its reverse (11104133), we get a palindrome (44244244).

The spelling of 33140111 in words is "thirty-three million, one hundred forty thousand, one hundred eleven".