Base | Representation |
---|---|
bin | 110000001110101100101… |
… | …101101000100010100100 |
3 | 102201211211110222001100200 |
4 | 300032230231220202210 |
5 | 413300210230211100 |
6 | 11014324300510500 |
7 | 461310606214602 |
oct | 60165455504244 |
9 | 12654743861320 |
10 | 3314317428900 |
11 | 106865986a245 |
12 | 45640624b430 |
13 | 1b070095b51a |
14 | b65b1740872 |
15 | 5b32dd38e00 |
hex | 303acb688a4 |
3314317428900 has 54 divisors (see below), whose sum is σ = 10388543854962. Its totient is φ = 883817980800.
The previous prime is 3314317428853. The next prime is 3314317428911. The reversal of 3314317428900 is 98247134133.
3314317428900 is a `hidden beast` number, since 331 + 4 + 31 + 7 + 4 + 289 + 0 + 0 = 666.
It can be written as a sum of positive squares in 3 ways, for example, as 349054092864 + 2965263336036 = 590808^2 + 1721994^2 .
It is a Harshad number since it is a multiple of its sum of digits (45).
It is an unprimeable number.
It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 1841286561 + ... + 1841288360.
Almost surely, 23314317428900 is an apocalyptic number.
3314317428900 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
3314317428900 is an abundant number, since it is smaller than the sum of its proper divisors (7074226426062).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3314317428900 is a wasteful number, since it uses less digits than its factorization.
3314317428900 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3682574941 (or 3682574931 counting only the distinct ones).
The product of its (nonzero) digits is 435456, while the sum is 45.
The spelling of 3314317428900 in words is "three trillion, three hundred fourteen billion, three hundred seventeen million, four hundred twenty-eight thousand, nine hundred".
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