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331470536489 is a prime number
BaseRepresentation
bin1001101001011010010…
…11101111111100101001
31011200120202021220221122
410310231023233330221
520412322424131424
6412135255545025
732643102033521
oct4645513577451
91150522256848
10331470536489
11118637527144
12542a898b175
1325346a6b231
14120869c0681
15895046245e
hex4d2d2eff29

331470536489 has 2 divisors, whose sum is σ = 331470536490. Its totient is φ = 331470536488.

The previous prime is 331470536483. The next prime is 331470536491. The reversal of 331470536489 is 984635074133.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 317776856089 + 13693680400 = 563717^2 + 117020^2 .

It is a cyclic number.

It is not a de Polignac number, because 331470536489 - 24 = 331470536473 is a prime.

Together with 331470536491, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 331470536489.

It is not a weakly prime, because it can be changed into another prime (331470536483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165735268244 + 165735268245.

It is an arithmetic number, because the mean of its divisors is an integer number (165735268245).

Almost surely, 2331470536489 is an apocalyptic number.

It is an amenable number.

331470536489 is a deficient number, since it is larger than the sum of its proper divisors (1).

331470536489 is an equidigital number, since it uses as much as digits as its factorization.

331470536489 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6531840, while the sum is 53.

The spelling of 331470536489 in words is "three hundred thirty-one billion, four hundred seventy million, five hundred thirty-six thousand, four hundred eighty-nine".