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33190251317 is a prime number
BaseRepresentation
bin11110111010010010…
…110000101100110101
310011200002022110110022
4132322102300230311
51020433201020232
623125234134525
72253325324046
oct367222605465
9104602273408
1033190251317
1113092039073
126523421445
13318c2cc582
14186c0168cd
15ce3c4d812
hex7ba4b0b35

33190251317 has 2 divisors, whose sum is σ = 33190251318. Its totient is φ = 33190251316.

The previous prime is 33190251299. The next prime is 33190251319. The reversal of 33190251317 is 71315209133.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 33155311396 + 34939921 = 182086^2 + 5911^2 .

It is a cyclic number.

It is not a de Polignac number, because 33190251317 - 26 = 33190251253 is a prime.

It is a super-2 number, since 2×331902513172 (a number of 22 digits) contains 22 as substring.

Together with 33190251319, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (33190251319) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16595125658 + 16595125659.

It is an arithmetic number, because the mean of its divisors is an integer number (16595125659).

Almost surely, 233190251317 is an apocalyptic number.

It is an amenable number.

33190251317 is a deficient number, since it is larger than the sum of its proper divisors (1).

33190251317 is an equidigital number, since it uses as much as digits as its factorization.

33190251317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17010, while the sum is 35.

The spelling of 33190251317 in words is "thirty-three billion, one hundred ninety million, two hundred fifty-one thousand, three hundred seventeen".