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3321401343317 is a prime number
BaseRepresentation
bin110000010101010010111…
…100100111110101010101
3102202112010011121012002022
4300111102330213311111
5413404212220441232
611021455233422525
7461651264412401
oct60252274476525
912675104535068
103321401343317
111070664518a72
1245786270aa45
131b128c465465
14b6a844a2101
155b5e5bcb812
hex30552f27d55

3321401343317 has 2 divisors, whose sum is σ = 3321401343318. Its totient is φ = 3321401343316.

The previous prime is 3321401343307. The next prime is 3321401343343. The reversal of 3321401343317 is 7133431041233.

It is a happy number.

3321401343317 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2384210839921 + 937190503396 = 1544089^2 + 968086^2 .

It is a cyclic number.

It is not a de Polignac number, because 3321401343317 - 222 = 3321397149013 is a prime.

It is a super-2 number, since 2×33214013433172 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3321401343307) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1660700671658 + 1660700671659.

It is an arithmetic number, because the mean of its divisors is an integer number (1660700671659).

Almost surely, 23321401343317 is an apocalyptic number.

It is an amenable number.

3321401343317 is a deficient number, since it is larger than the sum of its proper divisors (1).

3321401343317 is an equidigital number, since it uses as much as digits as its factorization.

3321401343317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54432, while the sum is 35.

The spelling of 3321401343317 in words is "three trillion, three hundred twenty-one billion, four hundred one million, three hundred forty-three thousand, three hundred seventeen".