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332142111102407 is a prime number
BaseRepresentation
bin100101110000101001101110…
…0100011000001010111000111
31121120000110211210121012010112
41023201103130203001113013
5322013304020420234112
63134223551314343235
7126650322100131224
oct11341233443012707
91546013753535115
10332142111102407
1196915750876a31
1231303448b8ab1b
1311343b36144828
145c03a9a3da94b
15285eba2843a22
hex12e14dc8c15c7

332142111102407 has 2 divisors, whose sum is σ = 332142111102408. Its totient is φ = 332142111102406.

The previous prime is 332142111102341. The next prime is 332142111102449. The reversal of 332142111102407 is 704201111241233.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 332142111102407 - 236 = 332073391625671 is a prime.

It is a super-2 number, since 2×3321421111024072 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (332142111101407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 166071055551203 + 166071055551204.

It is an arithmetic number, because the mean of its divisors is an integer number (166071055551204).

Almost surely, 2332142111102407 is an apocalyptic number.

332142111102407 is a deficient number, since it is larger than the sum of its proper divisors (1).

332142111102407 is an equidigital number, since it uses as much as digits as its factorization.

332142111102407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8064, while the sum is 32.

The spelling of 332142111102407 in words is "three hundred thirty-two trillion, one hundred forty-two billion, one hundred eleven million, one hundred two thousand, four hundred seven".