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3324425541407 is a prime number
BaseRepresentation
bin110000011000000111001…
…101000001011100011111
3102202210220221011100221222
4300120013031001130133
5413431410414311112
611023115304443555
7462116235600425
oct60300715013437
912683827140858
103324425541407
111071976606833
124583674795bb
131b1651b6cb99
14b6c8dda7115
155b721450372
hex3060734171f

3324425541407 has 2 divisors, whose sum is σ = 3324425541408. Its totient is φ = 3324425541406.

The previous prime is 3324425541401. The next prime is 3324425541433. The reversal of 3324425541407 is 7041455244233.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 3324425541407 - 216 = 3324425475871 is a prime.

It is a super-2 number, since 2×33244255414072 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3324425541401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1662212770703 + 1662212770704.

It is an arithmetic number, because the mean of its divisors is an integer number (1662212770704).

Almost surely, 23324425541407 is an apocalyptic number.

3324425541407 is a deficient number, since it is larger than the sum of its proper divisors (1).

3324425541407 is an equidigital number, since it uses as much as digits as its factorization.

3324425541407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1612800, while the sum is 44.

The spelling of 3324425541407 in words is "three trillion, three hundred twenty-four billion, four hundred twenty-five million, five hundred forty-one thousand, four hundred seven".