Base | Representation |
---|---|
bin | 10011110110010… |
… | …000101101101101 |
3 | 212012120201020122 |
4 | 103312100231231 |
5 | 1140221210331 |
6 | 53013054325 |
7 | 11152244144 |
oct | 2366205555 |
9 | 765521218 |
10 | 332991341 |
11 | 160a68361 |
12 | 936273a5 |
13 | 53cac4c7 |
14 | 3232075b |
15 | 1e37917b |
hex | 13d90b6d |
332991341 has 2 divisors, whose sum is σ = 332991342. Its totient is φ = 332991340.
The previous prime is 332991313. The next prime is 332991343. The reversal of 332991341 is 143199233.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 215355625 + 117635716 = 14675^2 + 10846^2 .
It is an emirp because it is prime and its reverse (143199233) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-332991341 is a prime.
It is a super-2 number, since 2×3329913412 = 221766466361956562, which contains 22 as substring.
Together with 332991343, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (332991343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 166495670 + 166495671.
It is an arithmetic number, because the mean of its divisors is an integer number (166495671).
Almost surely, 2332991341 is an apocalyptic number.
It is an amenable number.
332991341 is a deficient number, since it is larger than the sum of its proper divisors (1).
332991341 is an equidigital number, since it uses as much as digits as its factorization.
332991341 is an evil number, because the sum of its binary digits is even.
The product of its digits is 17496, while the sum is 35.
The square root of 332991341 is about 18248.0503342138. The cubic root of 332991341 is about 693.1240689696.
The spelling of 332991341 in words is "three hundred thirty-two million, nine hundred ninety-one thousand, three hundred forty-one".
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