33311312120057 has 2 divisors, whose sum is σ = 33311312120058. Its totient is φ = 33311312120056.

The previous prime is 33311312119991. The next prime is 33311312120059. The reversal of 33311312120057 is 75002121311333.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19223480722681 + 14087831397376 = 4384459^2 + 3753376^2 .

It is an emirp because it is prime and its reverse (75002121311333) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 33311312120057 - 2¹⁸ = 33311311857913 is a prime.

It is a super-2 number, since 2×33311312120057² (a number of 28 digits) contains 22 as substring.

Together with 33311312120059, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (33311312120059) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16655656060028 + 16655656060029.

It is an arithmetic number, because the mean of its divisors is an integer number (16655656060029).

Almost surely, 2^{33311312120057} is an apocalyptic number.

It is an amenable number.

33311312120057 is a deficient number, since it is larger than the sum of its proper divisors (1).

33311312120057 is an equidigital number, since it uses as much as digits as its factorization.

33311312120057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11340, while the sum is 32.

The spelling of 33311312120057 in words is "thirty-three trillion, three hundred eleven billion, three hundred twelve million, one hundred twenty thousand, fifty-seven".