Base | Representation |
---|---|
bin | 110000011110010111100… |
… | …010011100100111110111 |
3 | 102210110021000110001121212 |
4 | 300132113202130213313 |
5 | 414034134330403101 |
6 | 11030145554432035 |
7 | 462444543122165 |
oct | 60362742344767 |
9 | 12713230401555 |
10 | 3331142044151 |
11 | 1074802928749 |
12 | 45972089261b |
13 | 1b218250566c |
14 | b732a008235 |
15 | 5b9b5e1a1bb |
hex | 3079789c9f7 |
3331142044151 has 2 divisors, whose sum is σ = 3331142044152. Its totient is φ = 3331142044150.
The previous prime is 3331142044129. The next prime is 3331142044169. The reversal of 3331142044151 is 1514402411333.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3331142044151 - 210 = 3331142043127 is a prime.
It is a super-2 number, since 2×33311420441512 (a number of 26 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3331142046151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1665571022075 + 1665571022076.
It is an arithmetic number, because the mean of its divisors is an integer number (1665571022076).
Almost surely, 23331142044151 is an apocalyptic number.
3331142044151 is a deficient number, since it is larger than the sum of its proper divisors (1).
3331142044151 is an equidigital number, since it uses as much as digits as its factorization.
3331142044151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 32.
Adding to 3331142044151 its reverse (1514402411333), we get a palindrome (4845544455484).
The spelling of 3331142044151 in words is "three trillion, three hundred thirty-one billion, one hundred forty-two million, forty-four thousand, one hundred fifty-one".
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