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3331142044151 is a prime number
BaseRepresentation
bin110000011110010111100…
…010011100100111110111
3102210110021000110001121212
4300132113202130213313
5414034134330403101
611030145554432035
7462444543122165
oct60362742344767
912713230401555
103331142044151
111074802928749
1245972089261b
131b218250566c
14b732a008235
155b9b5e1a1bb
hex3079789c9f7

3331142044151 has 2 divisors, whose sum is σ = 3331142044152. Its totient is φ = 3331142044150.

The previous prime is 3331142044129. The next prime is 3331142044169. The reversal of 3331142044151 is 1514402411333.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 3331142044151 - 210 = 3331142043127 is a prime.

It is a super-2 number, since 2×33311420441512 (a number of 26 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3331142046151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1665571022075 + 1665571022076.

It is an arithmetic number, because the mean of its divisors is an integer number (1665571022076).

Almost surely, 23331142044151 is an apocalyptic number.

3331142044151 is a deficient number, since it is larger than the sum of its proper divisors (1).

3331142044151 is an equidigital number, since it uses as much as digits as its factorization.

3331142044151 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 3331142044151 its reverse (1514402411333), we get a palindrome (4845544455484).

The spelling of 3331142044151 in words is "three trillion, three hundred thirty-one billion, one hundred forty-two million, forty-four thousand, one hundred fifty-one".