Base | Representation |
---|---|
bin | 110000011110010111101… |
… | …111110010011011010011 |
3 | 102210110021021000201212001 |
4 | 300132113233302123103 |
5 | 414034141224310311 |
6 | 11030150201414431 |
7 | 462444614626066 |
oct | 60362757623323 |
9 | 12713237021761 |
10 | 3331145541331 |
11 | 10748048a7183 |
12 | 459721a9a417 |
13 | 1b218315b3ba |
14 | b732a6788dd |
15 | 5b9b63ab4c1 |
hex | 30797bf26d3 |
3331145541331 has 2 divisors, whose sum is σ = 3331145541332. Its totient is φ = 3331145541330.
The previous prime is 3331145541329. The next prime is 3331145541341. The reversal of 3331145541331 is 1331455411333.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3331145541331 - 21 = 3331145541329 is a prime.
It is a super-2 number, since 2×33311455413312 (a number of 26 digits) contains 22 as substring.
Together with 3331145541329, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (3331145541341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1665572770665 + 1665572770666.
It is an arithmetic number, because the mean of its divisors is an integer number (1665572770666).
Almost surely, 23331145541331 is an apocalyptic number.
3331145541331 is a deficient number, since it is larger than the sum of its proper divisors (1).
3331145541331 is an equidigital number, since it uses as much as digits as its factorization.
3331145541331 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 97200, while the sum is 37.
The spelling of 3331145541331 in words is "three trillion, three hundred thirty-one billion, one hundred forty-five million, five hundred forty-one thousand, three hundred thirty-one".
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