Base | Representation |
---|---|
bin | 110000011110010111101… |
… | …111110010011011011101 |
3 | 102210110021021000201212102 |
4 | 300132113233302123131 |
5 | 414034141224310331 |
6 | 11030150201414445 |
7 | 462444614626112 |
oct | 60362757623335 |
9 | 12713237021772 |
10 | 3331145541341 |
11 | 10748048a7192 |
12 | 459721a9a425 |
13 | 1b218315b3c7 |
14 | b732a678909 |
15 | 5b9b63ab4cb |
hex | 30797bf26dd |
3331145541341 has 2 divisors, whose sum is σ = 3331145541342. Its totient is φ = 3331145541340.
The previous prime is 3331145541331. The next prime is 3331145541377. The reversal of 3331145541341 is 1431455411333.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3315509289316 + 15636252025 = 1820854^2 + 125045^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3331145541341 is a prime.
It is a super-2 number, since 2×33311455413412 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3331145541295 and 3331145541304.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3331145541331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1665572770670 + 1665572770671.
It is an arithmetic number, because the mean of its divisors is an integer number (1665572770671).
Almost surely, 23331145541341 is an apocalyptic number.
It is an amenable number.
3331145541341 is a deficient number, since it is larger than the sum of its proper divisors (1).
3331145541341 is an equidigital number, since it uses as much as digits as its factorization.
3331145541341 is an evil number, because the sum of its binary digits is even.
The product of its digits is 129600, while the sum is 38.
The spelling of 3331145541341 in words is "three trillion, three hundred thirty-one billion, one hundred forty-five million, five hundred forty-one thousand, three hundred forty-one".
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