3331243141 has 2 divisors, whose sum is σ = 3331243142. Its totient is φ = 3331243140.

The previous prime is 3331243127. The next prime is 3331243151. The reversal of 3331243141 is 1413421333.

3331243141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3061298241 + 269944900 = 55329^2 + 16430^2 .

It is an emirp because it is prime and its reverse (1413421333) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3331243141 - 2¹⁵ = 3331210373 is a prime.

It is a super-2 number, since 2×3331243141² = 22194361728919091762, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3331243151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1665621570 + 1665621571.

It is an arithmetic number, because the mean of its divisors is an integer number (1665621571).

Almost surely, 2^3331243141 is an apocalyptic number.

It is an amenable number.

3331243141 is a deficient number, since it is larger than the sum of its proper divisors (1).

3331243141 is an equidigital number, since it uses as much as digits as its factorization.

3331243141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2592, while the sum is 25.

The square root of 3331243141 is about 57716.9224837915. The cubic root of 3331243141 is about 1493.4892836388.

Adding to 3331243141 its reverse (1413421333), we get a palindrome (4744664474).

The spelling of 3331243141 in words is "three billion, three hundred thirty-one million, two hundred forty-three thousand, one hundred forty-one".