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33314150413 is a prime number
BaseRepresentation
bin11111000001101011…
…011001100000001101
310011222201110012001201
4133001223121200031
51021211410303123
623145421505501
72256361414645
oct370153314015
9104881405051
1033314150413
1113145a73315
126558a12291
1331abb9014b
141880669525
15ceea745ad
hex7c1ad980d

33314150413 has 2 divisors, whose sum is σ = 33314150414. Its totient is φ = 33314150412.

The previous prime is 33314150357. The next prime is 33314150473. The reversal of 33314150413 is 31405141333.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 31770210564 + 1543939849 = 178242^2 + 39293^2 .

It is an emirp because it is prime and its reverse (31405141333) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 33314150413 - 221 = 33312053261 is a prime.

It is a super-2 number, since 2×333141504132 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (33314150473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16657075206 + 16657075207.

It is an arithmetic number, because the mean of its divisors is an integer number (16657075207).

Almost surely, 233314150413 is an apocalyptic number.

It is an amenable number.

33314150413 is a deficient number, since it is larger than the sum of its proper divisors (1).

33314150413 is an equidigital number, since it uses as much as digits as its factorization.

33314150413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6480, while the sum is 28.

Adding to 33314150413 its reverse (31405141333), we get a palindrome (64719291746).

The spelling of 33314150413 in words is "thirty-three billion, three hundred fourteen million, one hundred fifty thousand, four hundred thirteen".