Base | Representation |
---|---|
bin | 11111000110110111… |
… | …100111101101100111 |
3 | 10012012210022211002122 |
4 | 133012313213231213 |
5 | 1021401204143143 |
6 | 23202212300155 |
7 | 2261466600455 |
oct | 370667475547 |
9 | 105183284078 |
10 | 33401240423 |
11 | 13190147331 |
12 | 658201165b |
13 | 31c3c336b5 |
14 | 188c0599d5 |
15 | d07528c68 |
hex | 7c6de7b67 |
33401240423 has 2 divisors, whose sum is σ = 33401240424. Its totient is φ = 33401240422.
The previous prime is 33401240417. The next prime is 33401240429. The reversal of 33401240423 is 32404210433.
It is a balanced prime because it is at equal distance from previous prime (33401240417) and next prime (33401240429).
It is a cyclic number.
It is not a de Polignac number, because 33401240423 - 218 = 33400978279 is a prime.
It is a super-2 number, since 2×334012404232 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 33401240392 and 33401240401.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (33401240429) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16700620211 + 16700620212.
It is an arithmetic number, because the mean of its divisors is an integer number (16700620212).
Almost surely, 233401240423 is an apocalyptic number.
33401240423 is a deficient number, since it is larger than the sum of its proper divisors (1).
33401240423 is an equidigital number, since it uses as much as digits as its factorization.
33401240423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 26.
Adding to 33401240423 its reverse (32404210433), we get a palindrome (65805450856).
The spelling of 33401240423 in words is "thirty-three billion, four hundred one million, two hundred forty thousand, four hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •