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3340140201245 = 52712719906601
BaseRepresentation
bin110000100110101111110…
…111101100010100011101
3102211022111010001210122102
4300212233313230110131
5414211101342414440
611034234512254445
7463213534156301
oct60465767542435
912738433053572
103340140201245
111078600080311
1245b412241425
131b2c8778bb83
14b794109dd01
155bd40d80b15
hex309afdec51d

3340140201245 has 16 divisors (see below), whose sum is σ = 4024442542080. Its totient is φ = 2661269904000.

The previous prime is 3340140201221. The next prime is 3340140201247. The reversal of 3340140201245 is 5421020410433.

It is a de Polignac number, because none of the positive numbers 2k-3340140201245 is a prime.

It is a super-2 number, since 2×33401402012452 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3340140201247) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3230945 + ... + 4137545.

It is an arithmetic number, because the mean of its divisors is an integer number (251527658880).

Almost surely, 23340140201245 is an apocalyptic number.

It is an amenable number.

3340140201245 is a deficient number, since it is larger than the sum of its proper divisors (684302340835).

3340140201245 is a wasteful number, since it uses less digits than its factorization.

3340140201245 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 909596.

The product of its (nonzero) digits is 11520, while the sum is 29.

Adding to 3340140201245 its reverse (5421020410433), we get a palindrome (8761160611678).

The spelling of 3340140201245 in words is "three trillion, three hundred forty billion, one hundred forty million, two hundred one thousand, two hundred forty-five".

Divisors: 1 5 271 1355 2719 13595 736849 906601 3684245 4533005 245688871 1228444355 2465048119 12325240595 668028040249 3340140201245