Base | Representation |
---|---|
bin | 110000100110101111110… |
… | …111101100010100011110 |
3 | 102211022111010001210122110 |
4 | 300212233313230110132 |
5 | 414211101342414441 |
6 | 11034234512254450 |
7 | 463213534156302 |
oct | 60465767542436 |
9 | 12738433053573 |
10 | 3340140201246 |
11 | 1078600080312 |
12 | 45b412241426 |
13 | 1b2c8778bb84 |
14 | b794109dd02 |
15 | 5bd40d80b16 |
hex | 309afdec51e |
3340140201246 has 16 divisors (see below), whose sum is σ = 6680336979600. Its totient is φ = 1113370637568.
The previous prime is 3340140201221. The next prime is 3340140201247. The reversal of 3340140201246 is 6421020410433.
It is a super-5 number, since 5×33401402012465 (a number of 64 digits) contains 55555 as substring. Note that it is a super-d number also for d = 2.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3340140201247) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1569651 + ... + 3023918.
It is an arithmetic number, because the mean of its divisors is an integer number (417521061225).
Almost surely, 23340140201246 is an apocalyptic number.
3340140201246 is an abundant number, since it is smaller than the sum of its proper divisors (3340196778354).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3340140201246 is a wasteful number, since it uses less digits than its factorization.
3340140201246 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4714763.
The product of its (nonzero) digits is 13824, while the sum is 30.
Adding to 3340140201246 its reverse (6421020410433), we get a palindrome (9761160611679).
The spelling of 3340140201246 in words is "three trillion, three hundred forty billion, one hundred forty million, two hundred one thousand, two hundred forty-six".
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