Base | Representation |
---|---|
bin | 110000100110101111110… |
… | …111101100010100011111 |
3 | 102211022111010001210122111 |
4 | 300212233313230110133 |
5 | 414211101342414442 |
6 | 11034234512254451 |
7 | 463213534156303 |
oct | 60465767542437 |
9 | 12738433053574 |
10 | 3340140201247 |
11 | 1078600080313 |
12 | 45b412241427 |
13 | 1b2c8778bb85 |
14 | b794109dd03 |
15 | 5bd40d80b17 |
hex | 309afdec51f |
3340140201247 has 2 divisors, whose sum is σ = 3340140201248. Its totient is φ = 3340140201246.
The previous prime is 3340140201221. The next prime is 3340140201269. The reversal of 3340140201247 is 7421020410433.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3340140201247 is a prime.
It is a super-2 number, since 2×33401402012472 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3340140201347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1670070100623 + 1670070100624.
It is an arithmetic number, because the mean of its divisors is an integer number (1670070100624).
Almost surely, 23340140201247 is an apocalyptic number.
3340140201247 is a deficient number, since it is larger than the sum of its proper divisors (1).
3340140201247 is an equidigital number, since it uses as much as digits as its factorization.
3340140201247 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16128, while the sum is 31.
The spelling of 3340140201247 in words is "three trillion, three hundred forty billion, one hundred forty million, two hundred one thousand, two hundred forty-seven".
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