Base | Representation |
---|---|
bin | 110000100110101111110… |
… | …111101100010100100010 |
3 | 102211022111010001210122121 |
4 | 300212233313230110202 |
5 | 414211101342420000 |
6 | 11034234512254454 |
7 | 463213534156306 |
oct | 60465767542442 |
9 | 12738433053577 |
10 | 3340140201250 |
11 | 1078600080316 |
12 | 45b41224142a |
13 | 1b2c8778bb88 |
14 | b794109dd06 |
15 | 5bd40d80b1a |
hex | 309afdec522 |
3340140201250 has 40 divisors (see below), whose sum is σ = 6261402159936. Its totient is φ = 1335918786000.
The previous prime is 3340140201247. The next prime is 3340140201269. The reversal of 3340140201250 is 521020410433.
It is a super-2 number, since 2×33401402012502 (a number of 26 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is an unprimeable number.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 12496507 + ... + 12760993.
Almost surely, 23340140201250 is an apocalyptic number.
3340140201250 is a deficient number, since it is larger than the sum of its proper divisors (2921261958686).
3340140201250 is a wasteful number, since it uses less digits than its factorization.
3340140201250 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 274612 (or 274597 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 3340140201250 its reverse (521020410433), we get a palindrome (3861160611683).
The spelling of 3340140201250 in words is "three trillion, three hundred forty billion, one hundred forty million, two hundred one thousand, two hundred fifty".
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