3340400040433 has 2 divisors, whose sum is σ = 3340400040434. Its totient is φ = 3340400040432.

The previous prime is 3340400040431. The next prime is 3340400040437.

It is a happy number.

3340400040433 is nontrivially palindromic in base 10.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2253037024144 + 1087363016289 = 1501012^2 + 1042767^2 .

It is a palprime.

It is a cyclic number.

It is not a de Polignac number, because 3340400040433 - 2¹ = 3340400040431 is a prime.

It is a super-3 number, since 3×3340400040433³ (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 3340400040431, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (3340400040431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1670200020216 + 1670200020217.

It is an arithmetic number, because the mean of its divisors is an integer number (1670200020217).

Almost surely, 2^{3340400040433} is an apocalyptic number.

It is an amenable number.

3340400040433 is a deficient number, since it is larger than the sum of its proper divisors (1).

3340400040433 is an equidigital number, since it uses as much as digits as its factorization.

3340400040433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20736, while the sum is 28.

It can be divided in two parts, 33404000 and 40433, that added together give a palindrome (33444433).

The spelling of 3340400040433 in words is "three trillion, three hundred forty billion, four hundred million, forty thousand, four hundred thirty-three".