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334044411341 is a prime number
BaseRepresentation
bin1001101110001101001…
…10010011010111001101
31011221020010111022110212
410313012212103113031
520433110332130331
6413242523012205
733063634435034
oct4670646232715
91157203438425
10334044411341
111197383a8443
12548a696a065
1325667094ac4
141224c78171b
158a513d1d2b
hex4dc69935cd

334044411341 has 2 divisors, whose sum is σ = 334044411342. Its totient is φ = 334044411340.

The previous prime is 334044411313. The next prime is 334044411367. The reversal of 334044411341 is 143114440433.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 179221835716 + 154822575625 = 423346^2 + 393475^2 .

It is a cyclic number.

It is not a de Polignac number, because 334044411341 - 230 = 332970669517 is a prime.

It is a super-2 number, since 2×3340444113412 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 334044411298 and 334044411307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (334044431341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167022205670 + 167022205671.

It is an arithmetic number, because the mean of its divisors is an integer number (167022205671).

Almost surely, 2334044411341 is an apocalyptic number.

It is an amenable number.

334044411341 is a deficient number, since it is larger than the sum of its proper divisors (1).

334044411341 is an equidigital number, since it uses as much as digits as its factorization.

334044411341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 334044411341 its reverse (143114440433), we get a palindrome (477158851774).

The spelling of 334044411341 in words is "three hundred thirty-four billion, forty-four million, four hundred eleven thousand, three hundred forty-one".