Base | Representation |
---|---|
bin | 100101111111001000010101… |
… | …1010110101010010011010111 |
3 | 1121211001201002210111100102112 |
4 | 1023332100223112222103113 |
5 | 322243404320244322333 |
6 | 3142350042334301235 |
7 | 130244145344165651 |
oct | 11376205326522327 |
9 | 1554051083440375 |
10 | 334132003120343 |
11 | 9751264aa5a22a |
12 | 3158502b95781b |
13 | 11459688511a0c |
14 | 5c7210a6596d1 |
15 | 2896818233948 |
hex | 12fe42b5aa4d7 |
334132003120343 has 2 divisors, whose sum is σ = 334132003120344. Its totient is φ = 334132003120342.
The previous prime is 334132003120309. The next prime is 334132003120417. The reversal of 334132003120343 is 343021300231433.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 334132003120343 - 214 = 334132003103959 is a prime.
It is a super-2 number, since 2×3341320031203432 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (334132003129343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167066001560171 + 167066001560172.
It is an arithmetic number, because the mean of its divisors is an integer number (167066001560172).
Almost surely, 2334132003120343 is an apocalyptic number.
334132003120343 is a deficient number, since it is larger than the sum of its proper divisors (1).
334132003120343 is an equidigital number, since it uses as much as digits as its factorization.
334132003120343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 46656, while the sum is 32.
Adding to 334132003120343 its reverse (343021300231433), we get a palindrome (677153303351776).
The spelling of 334132003120343 in words is "three hundred thirty-four trillion, one hundred thirty-two billion, three million, one hundred twenty thousand, three hundred forty-three".
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