Base | Representation |
---|---|
bin | 1111001100101011111000… |
… | …01100001111000000010111 |
3 | 11101100001000120110000100212 |
4 | 13212111330030033000113 |
5 | 13340033131333042101 |
6 | 155025255353200035 |
7 | 10016414042463311 |
oct | 746257414170027 |
9 | 141301016400325 |
10 | 33421224112151 |
11 | a7159527a3787 |
12 | 38b931040001b |
13 | 15857b976c615 |
14 | 83784b1367b1 |
15 | 3ce5693821bb |
hex | 1e657c30f017 |
33421224112151 has 2 divisors, whose sum is σ = 33421224112152. Its totient is φ = 33421224112150.
The previous prime is 33421224112097. The next prime is 33421224112181. The reversal of 33421224112151 is 15121142212433.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 33421224112151 - 210 = 33421224111127 is a prime.
It is a super-2 number, since 2×334212241121512 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (33421224112181) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16710612056075 + 16710612056076.
It is an arithmetic number, because the mean of its divisors is an integer number (16710612056076).
Almost surely, 233421224112151 is an apocalyptic number.
33421224112151 is a deficient number, since it is larger than the sum of its proper divisors (1).
33421224112151 is an equidigital number, since it uses as much as digits as its factorization.
33421224112151 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 11520, while the sum is 32.
Adding to 33421224112151 its reverse (15121142212433), we get a palindrome (48542366324584).
The spelling of 33421224112151 in words is "thirty-three trillion, four hundred twenty-one billion, two hundred twenty-four million, one hundred twelve thousand, one hundred fifty-one".
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