Base | Representation |
---|---|
bin | 110000101000111101010… |
… | …100110110101100111000 |
3 | 102211112121111201111010122 |
4 | 300220331110312230320 |
5 | 414230431414332100 |
6 | 11035310211032412 |
7 | 463326412255421 |
oct | 60507524665470 |
9 | 12745544644118 |
10 | 3342513433400 |
11 | 107960876a7a9 |
12 | 45b974b9b708 |
13 | 1b3275364a5b |
14 | b7ac8352648 |
15 | 5be2e3ba985 |
hex | 30a3d536b38 |
3342513433400 has 48 divisors (see below), whose sum is σ = 7887333969240. Its totient is φ = 1317050064000.
The previous prime is 3342513433381. The next prime is 3342513433433. The reversal of 3342513433400 is 43343152433.
3342513433400 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×33425134334002 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 124707251 + ... + 124734050.
Almost surely, 23342513433400 is an apocalyptic number.
It is an amenable number.
3342513433400 is an abundant number, since it is smaller than the sum of its proper divisors (4544820535840).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3342513433400 is a wasteful number, since it uses less digits than its factorization.
3342513433400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 249441384 (or 249441375 counting only the distinct ones).
The product of its (nonzero) digits is 155520, while the sum is 35.
Adding to 3342513433400 its reverse (43343152433), we get a palindrome (3385856585833).
The spelling of 3342513433400 in words is "three trillion, three hundred forty-two billion, five hundred thirteen million, four hundred thirty-three thousand, four hundred".
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