Base | Representation |
---|---|
bin | 1100011110100101… |
… | …1110110100011011 |
3 | 22122102202021020121 |
4 | 3013221132310123 |
5 | 23324440240443 |
6 | 1312212134111 |
7 | 146001423046 |
oct | 30751366433 |
9 | 8572667217 |
10 | 3349540123 |
11 | 1469801086 |
12 | 795907337 |
13 | 414c39307 |
14 | 23abd3c5d |
15 | 1490db4ed |
hex | c7a5ed1b |
3349540123 has 2 divisors, whose sum is σ = 3349540124. Its totient is φ = 3349540122.
The previous prime is 3349540099. The next prime is 3349540147. The reversal of 3349540123 is 3210459433.
It is a balanced prime because it is at equal distance from previous prime (3349540099) and next prime (3349540147).
It is a cyclic number.
It is not a de Polignac number, because 3349540123 - 213 = 3349531931 is a prime.
It is a super-2 number, since 2×33495401232 = 22438838071173710258, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3349541123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1674770061 + 1674770062.
It is an arithmetic number, because the mean of its divisors is an integer number (1674770062).
Almost surely, 23349540123 is an apocalyptic number.
3349540123 is a deficient number, since it is larger than the sum of its proper divisors (1).
3349540123 is an equidigital number, since it uses as much as digits as its factorization.
3349540123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 38880, while the sum is 34.
The square root of 3349540123 is about 57875.2116454013. The cubic root of 3349540123 is about 1496.2186419346.
Adding to 3349540123 its reverse (3210459433), we get a palindrome (6559999556).
The spelling of 3349540123 in words is "three billion, three hundred forty-nine million, five hundred forty thousand, one hundred twenty-three".
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