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335152140343 is a prime number
BaseRepresentation
bin1001110000010001001…
…11111101000000110111
31012001002022212202222221
410320020213331000313
520442342421442333
6413544453303211
733133245121456
oct4701047750067
91161068782887
10335152140343
1111a156711659
1254b55934b07
13257b2720757
1412315932b9d
158ab8792d2d
hex4e089fd037

335152140343 has 2 divisors, whose sum is σ = 335152140344. Its totient is φ = 335152140342.

The previous prime is 335152140229. The next prime is 335152140371. The reversal of 335152140343 is 343041251533.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 335152140343 - 217 = 335152009271 is a prime.

It is a super-2 number, since 2×3351521403432 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 335152140299 and 335152140308.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (335152144343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 167576070171 + 167576070172.

It is an arithmetic number, because the mean of its divisors is an integer number (167576070172).

Almost surely, 2335152140343 is an apocalyptic number.

335152140343 is a deficient number, since it is larger than the sum of its proper divisors (1).

335152140343 is an equidigital number, since it uses as much as digits as its factorization.

335152140343 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64800, while the sum is 34.

Adding to 335152140343 its reverse (343041251533), we get a palindrome (678193391876).

The spelling of 335152140343 in words is "three hundred thirty-five billion, one hundred fifty-two million, one hundred forty thousand, three hundred forty-three".