3395311461341 has 2 divisors, whose sum is σ = 3395311461342. Its totient is φ = 3395311461340.

The previous prime is 3395311461331. The next prime is 3395311461343. The reversal of 3395311461341 is 1431641135933.

3395311461341 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3260115525241 + 135195936100 = 1805579^2 + 367690^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3395311461341 is a prime.

Together with 3395311461343, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 3395311461292 and 3395311461301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3395311461343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1697655730670 + 1697655730671.

It is an arithmetic number, because the mean of its divisors is an integer number (1697655730671).

Almost surely, 2^{3395311461341} is an apocalyptic number.

It is an amenable number.

3395311461341 is a deficient number, since it is larger than the sum of its proper divisors (1).

3395311461341 is an equidigital number, since it uses as much as digits as its factorization.

3395311461341 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 349920, while the sum is 44.

The spelling of 3395311461341 in words is "three trillion, three hundred ninety-five billion, three hundred eleven million, four hundred sixty-one thousand, three hundred forty-one".