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340024125303437 is a prime number
BaseRepresentation
bin100110101010000000000100…
…1001101000010101010001101
31122120220222200220212222212112
41031110000021031002222031
5324031423402034202222
63203100532101313405
7131422634542324331
oct11524001115025215
91576828626788775
10340024125303437
11993844703610a3
1232176b53705865
13117961a2c2b753
145dd73810477c1
152949c1b56dbe2
hex1354009342a8d

340024125303437 has 2 divisors, whose sum is σ = 340024125303438. Its totient is φ = 340024125303436.

The previous prime is 340024125303407. The next prime is 340024125303509. The reversal of 340024125303437 is 734303521420043.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 331707759419716 + 8316365883721 = 18212846^2 + 2883811^2 .

It is a cyclic number.

It is not a de Polignac number, because 340024125303437 - 214 = 340024125287053 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 340024125303394 and 340024125303403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (340024125303407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 170012062651718 + 170012062651719.

It is an arithmetic number, because the mean of its divisors is an integer number (170012062651719).

Almost surely, 2340024125303437 is an apocalyptic number.

It is an amenable number.

340024125303437 is a deficient number, since it is larger than the sum of its proper divisors (1).

340024125303437 is an equidigital number, since it uses as much as digits as its factorization.

340024125303437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 725760, while the sum is 41.

The spelling of 340024125303437 in words is "three hundred forty trillion, twenty-four billion, one hundred twenty-five million, three hundred three thousand, four hundred thirty-seven".