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3400520402509 is a prime number
BaseRepresentation
bin110001011110111110110…
…011111000011001001101
3110001002100010001211110221
4301132332303320121031
5421203231210340014
611122102201431341
7500452031335426
oct61367663703115
913032303054427
103400520402509
1110a117513019a
1246b06349b551
131b888ac17a09
14ba82c24264d
155d6c6b85b24
hex317becf864d

3400520402509 has 2 divisors, whose sum is σ = 3400520402510. Its totient is φ = 3400520402508.

The previous prime is 3400520402479. The next prime is 3400520402567. The reversal of 3400520402509 is 9052040250043.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3400520402500 + 9 = 1844050^2 + 3^2 .

It is a cyclic number.

It is not a de Polignac number, because 3400520402509 - 213 = 3400520394317 is a prime.

It is a super-3 number, since 3×34005204025093 (a number of 39 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3400520402009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1700260201254 + 1700260201255.

It is an arithmetic number, because the mean of its divisors is an integer number (1700260201255).

Almost surely, 23400520402509 is an apocalyptic number.

It is an amenable number.

3400520402509 is a deficient number, since it is larger than the sum of its proper divisors (1).

3400520402509 is an equidigital number, since it uses as much as digits as its factorization.

3400520402509 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43200, while the sum is 34.

The spelling of 3400520402509 in words is "three trillion, four hundred billion, five hundred twenty million, four hundred two thousand, five hundred nine".