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3400550170481 is a prime number
BaseRepresentation
bin110001011111000000100…
…101011011111101110001
3110001002102012002012110102
4301133000211123331301
5421203311320423411
611122105143442145
7500452542346502
oct61370045337561
913032365065412
103400550170481
1110a118aa12322
1246b071456355
131b889413b1b9
14ba832190ba9
155d6c95b5d3b
hex317c095bf71

3400550170481 has 2 divisors, whose sum is σ = 3400550170482. Its totient is φ = 3400550170480.

The previous prime is 3400550170411. The next prime is 3400550170483. The reversal of 3400550170481 is 1840710550043.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3327855226081 + 72694944400 = 1824241^2 + 269620^2 .

It is a cyclic number.

It is not a de Polignac number, because 3400550170481 - 218 = 3400549908337 is a prime.

It is a super-2 number, since 2×34005501704812 (a number of 26 digits) contains 22 as substring.

Together with 3400550170483, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (3400550170483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1700275085240 + 1700275085241.

It is an arithmetic number, because the mean of its divisors is an integer number (1700275085241).

Almost surely, 23400550170481 is an apocalyptic number.

It is an amenable number.

3400550170481 is a deficient number, since it is larger than the sum of its proper divisors (1).

3400550170481 is an equidigital number, since it uses as much as digits as its factorization.

3400550170481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 67200, while the sum is 38.

The spelling of 3400550170481 in words is "three trillion, four hundred billion, five hundred fifty million, one hundred seventy thousand, four hundred eighty-one".