Base | Representation |
---|---|
bin | 110001011111101111101… |
… | …010110100011010100111 |
3 | 110001011110020111022110021 |
4 | 301133233222310122213 |
5 | 421211421032014003 |
6 | 11122315402540011 |
7 | 500511243623566 |
oct | 61375752643247 |
9 | 13034406438407 |
10 | 3401340110503 |
11 | 10a1555901a15 |
12 | 46b251b07607 |
13 | 1b898b9ab12a |
14 | ba8a905bbdd |
15 | 5d723b022bd |
hex | 317efab46a7 |
3401340110503 has 2 divisors, whose sum is σ = 3401340110504. Its totient is φ = 3401340110502.
The previous prime is 3401340110477. The next prime is 3401340110533. The reversal of 3401340110503 is 3050110431043.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3401340110503 - 213 = 3401340102311 is a prime.
It is a super-2 number, since 2×34013401105032 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3401340110533) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1700670055251 + 1700670055252.
It is an arithmetic number, because the mean of its divisors is an integer number (1700670055252).
Almost surely, 23401340110503 is an apocalyptic number.
3401340110503 is a deficient number, since it is larger than the sum of its proper divisors (1).
3401340110503 is an equidigital number, since it uses as much as digits as its factorization.
3401340110503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 3401340110503 its reverse (3050110431043), we get a palindrome (6451450541546).
The spelling of 3401340110503 in words is "three trillion, four hundred one billion, three hundred forty million, one hundred ten thousand, five hundred three".
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