Base | Representation |
---|---|
bin | 1111011110001011101010… |
… | …10100011011111101100101 |
3 | 11110110111202211220221110012 |
4 | 13233011311110123331211 |
5 | 13424410340441241201 |
6 | 200205402101540005 |
7 | 10111015615335035 |
oct | 757056524337545 |
9 | 143414684827405 |
10 | 34022404243301 |
11 | a927903262281 |
12 | 399592a414605 |
13 | 15ca3b6a55786 |
14 | 85899c0178c5 |
15 | 3e0002b135bb |
hex | 1ef17551bf65 |
34022404243301 has 2 divisors, whose sum is σ = 34022404243302. Its totient is φ = 34022404243300.
The previous prime is 34022404243283. The next prime is 34022404243381. The reversal of 34022404243301 is 10334240422043.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 17222251000900 + 16800153242401 = 4149970^2 + 4098799^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-34022404243301 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34022404243381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17011202121650 + 17011202121651.
It is an arithmetic number, because the mean of its divisors is an integer number (17011202121651).
Almost surely, 234022404243301 is an apocalyptic number.
It is an amenable number.
34022404243301 is a deficient number, since it is larger than the sum of its proper divisors (1).
34022404243301 is an equidigital number, since it uses as much as digits as its factorization.
34022404243301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 55296, while the sum is 32.
Adding to 34022404243301 its reverse (10334240422043), we get a palindrome (44356644665344).
The spelling of 34022404243301 in words is "thirty-four trillion, twenty-two billion, four hundred four million, two hundred forty-three thousand, three hundred one".
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