Base | Representation |
---|---|
bin | 11111101100011101… |
… | …111110000010100101 |
3 | 10020211202022021121221 |
4 | 133230131332002211 |
5 | 1024144201102331 |
6 | 23344544540341 |
7 | 2313226440442 |
oct | 375435760245 |
9 | 106752267557 |
10 | 34032050341 |
11 | 13484229143 |
12 | 67193216b1 |
13 | 3294828ac3 |
14 | 190bb429c9 |
15 | d42ad0711 |
hex | 7ec77e0a5 |
34032050341 has 2 divisors, whose sum is σ = 34032050342. Its totient is φ = 34032050340.
The previous prime is 34032050329. The next prime is 34032050347. The reversal of 34032050341 is 14305023043.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 33938850625 + 93199716 = 184225^2 + 9654^2 .
It is an emirp because it is prime and its reverse (14305023043) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 34032050341 - 233 = 25442115749 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34032050347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17016025170 + 17016025171.
It is an arithmetic number, because the mean of its divisors is an integer number (17016025171).
Almost surely, 234032050341 is an apocalyptic number.
It is an amenable number.
34032050341 is a deficient number, since it is larger than the sum of its proper divisors (1).
34032050341 is an equidigital number, since it uses as much as digits as its factorization.
34032050341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 25.
Adding to 34032050341 its reverse (14305023043), we get a palindrome (48337073384).
The spelling of 34032050341 in words is "thirty-four billion, thirty-two million, fifty thousand, three hundred forty-one".
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