Base | Representation |
---|---|
bin | 11111101100111110… |
… | …001111101010101111 |
3 | 10020212100020010200021 |
4 | 133230332033222233 |
5 | 1024203332324101 |
6 | 23345450143011 |
7 | 2313361366513 |
oct | 375476175257 |
9 | 106770203607 |
10 | 34040511151 |
11 | 13488a87949 |
12 | 6720121a67 |
13 | 32964cbbba |
14 | 190cd06143 |
15 | d437025a1 |
hex | 7ecf8faaf |
34040511151 has 2 divisors, whose sum is σ = 34040511152. Its totient is φ = 34040511150.
The previous prime is 34040511143. The next prime is 34040511157. The reversal of 34040511151 is 15111504043.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 34040511151 - 23 = 34040511143 is a prime.
It is a super-3 number, since 3×340405111513 (a number of 33 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34040511157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17020255575 + 17020255576.
It is an arithmetic number, because the mean of its divisors is an integer number (17020255576).
Almost surely, 234040511151 is an apocalyptic number.
34040511151 is a deficient number, since it is larger than the sum of its proper divisors (1).
34040511151 is an equidigital number, since it uses as much as digits as its factorization.
34040511151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1200, while the sum is 25.
The spelling of 34040511151 in words is "thirty-four billion, forty million, five hundred eleven thousand, one hundred fifty-one".
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